(2x+3)(5x^2-21x+4)=0

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Solution for (2x+3)(5x^2-21x+4)=0 equation: 


Simplifying
(2x + 3)(5x2 + -21x + 4) = 0

Reorder the terms:
(3 + 2x)(5x2 + -21x + 4) = 0

Reorder the terms:
(3 + 2x)(4 + -21x + 5x2) = 0

Multiply (3 + 2x) * (4 + -21x + 5x2)
(3(4 + -21x + 5x2) + 2x * (4 + -21x + 5x2)) = 0
((4 * 3 + -21x * 3 + 5x2 * 3) + 2x * (4 + -21x + 5x2)) = 0
((12 + -63x + 15x2) + 2x * (4 + -21x + 5x2)) = 0
(12 + -63x + 15x2 + (4 * 2x + -21x * 2x + 5x2 * 2x)) = 0
(12 + -63x + 15x2 + (8x + -42x2 + 10x3)) = 0

Reorder the terms:
(12 + -63x + 8x + 15x2 + -42x2 + 10x3) = 0

Combine like terms: -63x + 8x = -55x
(12 + -55x + 15x2 + -42x2 + 10x3) = 0

Combine like terms: 15x2 + -42x2 = -27x2
(12 + -55x + -27x2 + 10x3) = 0

Solving
12 + -55x + -27x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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